(a) Forces and act on a body. Find the : (i) resultant of these forces ; (ii) fifth force that will keep the body in equilibrium. (b) A body moving at 20 ms accelerates uniformly at 2.5 ms for 4 seconds. It continues the journey at the speed for 8 seconds, before coming to rest in t seconds with a uniform retardation. If the ratio of the acceleration to the retardation is 3 : 4, (i) sketch the velocity- time graph of the journey ; (ii) find t ; (iii) find the total distance of the journey.
Explanation
(a) (i) (ii) Let the fifth force be F. (b) (i) Acceleration = a = 2.5 ms, Let retardation be r ms. (ii) We use the formula for the retardation period. (iii) Total distance = area under graph. Total distance = 100m + 240m + 135m = 475m.