The gradient of a curve at the point (-2, 0) is \(3x^{2} - 4x\). Find the equation of the curve.
A. \(y = 6x - 4\) B. \(y = 6x^{2} - 4x + 12\) C. \(y = x^{3} - 2x^{2}\) D. \(y = x^{3} - 2x^{2} + 16\)
Correct Answer: D
Explanation
The gradient of a curve is gotten by differentiating the equation of the curve. Therefore, given the gradient, integrate to get the equation of the curve back.