Total of four numbers \(=12145\)
average of these numbers \(=\frac{12145}{4_5}\)
we take both digits to base 10 thereafter, we divide in base 10 and finally convert to base \(5 .\)
Let's see how!
\(1^3 2^2 1^1 4_5^0 \rightarrow 10\)
\(\Rightarrow 1 \times 5^3+2 \times 5^2+1 \times 5+4\)
\(=125+2 \times 25+5+4\)
\(=184_{10}\)
also \(4_5 \rightarrow 10=4_{10}\)
then \(\frac{184}{4}=46_{10}\)
now \(46{ }_{10}\) to base 5