In a card of playing cards, there are a total of 52 cards of which 13 are spades and 13 are hearts.
Since the picking was done with replacement. then
P(The two cards are both spades and hearts) \(=P\left(1^{\text {st }}\right.\) card spade and second spade \()\) or \(P\left(1^{\text {st }}\right.\) card heart and second card heart)
\begin{array}{l}
\Rightarrow P\left[\left(\begin{array}{c}
1 \text { st } \\
\text { spade }
\end{array}\right) \times\left(\begin{array}{c}
2 \text { nd } \\
\text { spade }
\end{array}\right)\right]+\left[\left(\begin{array}{c}
\text { Ist } \\
\text { heart }
\end{array}\right) \times\left(\begin{array}{c}
2 \text { nd } \\
\text { heart }
\end{array}\right)\right] \\
=\left(\frac{13}{52} \times \frac{13}{52}\right)+\left(\frac{13}{52} \times \frac{13}{52}\right) \\
=2\left(\frac{13}{52} \times \frac{13}{52}\right)=\frac{1}{8}
\end{array}