Calculate the work done by a bricklayer who lifted a cement block of mass \(10 \mathrm{~kg}\) from the floor to a height of \(2.5 \mathrm{~m}\) (acceleration due to gravity \(=9.8 \mathrm{~m}^{-2}\) )
A. \(294.0 \mathrm{~J}\) B. \(245.0 \mathrm{~J}\) C. \(30.0 \mathrm{~J}\) D. \(25.0 \mathrm{~J}\)
Correct Answer: B
Explanation
given: mass \(=10 \mathrm{~kg}, \mathrm{~h}=2.5 \mathrm{~m}\) \(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2\) workdone \(=\) force \(\mathrm{x}\) distance moved in the direction of the force workdone \(=\mathrm{mgh}\) \(=10 \times 9.8 \times 2.5=245 \mathrm{~J}\)
