\(5.3 \mathrm{~g}\) of silver trioxonitrate (V) was dissolved in \(50 \mathrm{~cm}^3\) of water at \(25^{\circ} \mathrm{C}\). Calculate the solubility of the salt in moldm [Ag=108, N=14, O=16]
A. \(0.312 \mathrm{moldm}^3\) B. \(0.031 \mathrm{moldm}^3\) C. \(0.062 \mathrm{moldm}^3\) D. \(0.623 \mathrm{moldm}^3\)
Correct Answer: D
Explanation
\(\mathrm{AgNO}_3=(108+14+48) \mathrm{gmol}^{-1}\) \(=170 \mathrm{gmol}^{-1}\). Mole of \(\mathrm{AgNO}_3=\frac{5.3 \mathrm{~g}}{170 \mathrm{gmol}^{-1}}=0.03118 \mathrm{~mol}\) Volume of water \(=50 \mathrm{~cm}^3=\left(\frac{50}{1000}\right) \mathrm{dm}^3\) \(=0.05 \mathrm{dm}^3\) Solubility \(\left(\right.\) in moldm \(^{-3}\) ) \(=\frac{0.03118 \mathrm{~mol}^2}{0.05 \mathrm{dm}^3}\) \(=0.6236 \mathrm{moldm}^{-3}\)
