Which of the following alkanols will not undergo oxidation reaction by acidified \(K _{2} Cr _{2} O _{7}\) ?
A. \(CH _{3} CH _{2} CH ( OH )\) \(CH _{3}\) B. \(CH _{3} CH _{2} CH _{2} CH _{2} OH\) C. \(CH _{3} CH _{2} CH _{2} C \left( CH _{3}\right)( OH )\) \(CH _{3} \) D. None of the above
Correct Answer: D
Explanation
Acidified \(K _{2} Cr _{2} O _{7}\) oxidizes primary alkanol to alkanal and then to alkanoic acidcidified \(K _{2} C\) kanone only. It has no effect on tertiary \(\left(3^{\circ}\right)\) alkanol \(RCHR ^{\prime} \stackrel{\frac{ K , Cr , O , O }{\longrightarrow}}{\longrightarrow}\) No reaction \(3^{\circ}\) alkanol \(CH _{3} CH _{2} CH ( OH ) CH _{3}\) is a secondary alkanol (Butan - \(2-\) ol) which will be oxidized to butanone. \(CH _{3} CH _{2} CH _{2} OH\) is a primary alkanol (butan \(-1- ol\) ) that is oxidized to butanal \(\left( CH _{3} CH _{2} H _{2} CHO \right)\) \(CH _{3} CH _{2} CH _{2} C \left( CH _{3}\right)( OH ) CH _{3}\) is a tertiaryalkanol (2 methylpentan \(-2-01)\) which does not undergo oxidation with acidified \(K _{2} Cr _{2} O _{7}\).