A mole of a compound contains \(54 g\) of \(Al\) atoms, \(1.806\) \(\times 10^{24}\) of Sulphur atoms and \(192 g\) of oxygen atoms. The molecular formula of the compound is? [ \(Al =27, S =32\), \(\left.O =16, N _{ A }=6.02 \times 10^{23}\right]\)
A. \(AlSO _{3}\) B. \(Al _{2} S _{2} O _{2}\) C. \(Al _{2} SO _{2} \) D. \(Al _{2}\left( SO _{4}\right)_{3}\)
Correct Answer: D
Explanation
\(\begin{array}{ccc}\text { Al } & \text { S } & O \\ \frac{54}{27} & \frac{1.806 \times 10^{24}}{6.02 \times 10^{23}} & \frac{192}{16} \\ 2 & 3 & 12\end{array}\) Thus, the molecular formula of the compound is \(Al _{2}\left( SO _{4}\right)_{3}\)
