Which shell and orbital respectively is the location of an electron having the quantum numbers ____________
Explanation
When the principal quantum number, \(n\) is 1 , it is k-shell, when \(n=2\), it is L-shell when \(n=3\) it is M-shell, when \(n\) \(=4\), it is \(N\)-shell and so on. When the azimuthal quantum number is 0 , it is s-orbital, when \(l=1\), it is \(p\)-orbital, when \(l=2\), it is d-orbital and when \(l=3\), it is f-orbital. Then, when \(n=3\) and \(l=2\), the shell is \(m\)-shell and the orbital is d-orbital. N.B: when the azimuthal quantum number is \(x\), the magnetic quantum \(m\), will range from \(-x\) to \(+x\). so when \(l=2\), the possible values of \(m_{1}\) are \(-2,-1,0,1\) and 2