\(\begin{aligned} CaCO _{3}+2 HCl \rightarrow CaCl _{2}+ H _{2} O + CO _{2} \\ \eta_{ CaCO _{3}} &=\frac{5 g }{100 gmol ^{-1}}=0.05 mol \\ \eta_{ CaCO _{1}}: \eta_{ CO _{2}}=1: 1 \end{aligned}\)
Thus,
\begin{aligned}
\eta_{ Co _{2}} &=0.05 mol \\
\left(\begin{array}{c}
\text { Volume } \\
\text { at stp }
\end{array}\right) &=\text { mole } \times G \cdot M . V \\
&=(0.05 \times 22.4) dm ^{3} \\
&=1.12 dm ^{3}
\end{aligned}