\begin{aligned}
&1 Cu ^{2+}=2 F \\
&64 g =193000 C
\end{aligned}
Therefore, \(2.4 g\) of copper will be produced by
\begin{aligned}
&\left(\frac{193000}{64} \times 2.4\right) \text { C of electricity } \\
&Q=I t, I=\frac{Q}{t}=\left(\frac{7237.5}{750}\right) A \\
&=9.65 A
\end{aligned}