(a)(i) Diffusion is the movement of particles from the region of higher concentration to the region of lower concentration
(ii) Charles' Law states that the volume of a given mass of gas is directly proportional to its absolute temperature at a constant pressure.
(iii)
OR

(iv) \(\frac{V_1}{T_1} = \frac{V_2}{T_2}\) \(T_2 = \frac{T_1V_2}{V_1}\)
\(T_2 = \frac{300 \times 300}{150} = 600k\)
(v)(i) Solid < liquid < gas / solid, liquid, gas
(ii) Gas < liquid < Solid / gas, liquid, solid
b)(i) In a reversible reaction at equilibrium, if any will of the factors affecting the equilibrium is altered, the position of equilibrium will change so as to annul the effect of the change
(ii) Oxide I
% of O\(_2\) = 11.1 %
% by mass of metal = 88.9%
11.1 of O\(_2\) combined with 88.9 of metal
100 of O\(_2\) = \(\frac{100}{88.9}\) = 800.9g

Oxide II
% of O\(_2\) = 20%
% by mass of metal = 80%
20 of O\(_2\) combined with 80 of metal
100 of O\(_2\) = \(\frac{100}{ 80}\) = 400g
Ratio of metal in both oxides = 800. 9 : 400
2 : 1

(c)(i) Add water to mixture A, B and C and stir.
— C dissolves
— Filter to obtain C as filtrate and A and B as residue
— Heat residue until melted.
— Separate by simple distillation
— Evaporate filtrate to dryness to obtain solid C
— Pure A is collected at 117°C and pure B at 160°C

(ii) Mass of mixture = 25.25g
Mass A + B = 7.52g + 8.48g
= 16.00g
Mass of C = 25.25 - 16.00g
= 9.25g
% of C in mixture = \(\frac{9.25}{25.25}\) x 100
= 36.6%