a) Define the following in term:. of electron transfer: (i) oxidation; (ii) reduction. (b)(i) Determina the oxidation stale of phosphorus in each of the following structures: I. POCI II. PH. (ii) State with reasons whether the following compounds will form acidic, neutral or basic aqueous solutions: I. NaNO II. NaHCI; Ill. NaCO. (c) Consider the set-up
(i) What is the gas produced in the experiment illustrated by the set-up above? (ii) Name the method of collection of gas (iii) Give a reason for your answer in (c)(ii) above (iv) State the function of the concentrated HSO in the conical flask (v) Give of collection of the gas one I. physical property; II. chemical property of the gas (vi) State one chemical test to identify the gas. (d) A 4.3 g hydrated sodium tetraoxosulphate (VI) (NaSO.xHO) was heated to remove the water of crystallization. The remaining anhydrous salt had a mass of 2.12 g. Calculate the value of x in the t I hydrated salt. [H = 1; O = 16; Na = 23; S = 32 ]
Explanation
(a)(i) Oxidation is the process of electron loss. Reduction is the process of electron gain (b)(i) POCI O.N of P + O.N of oxygen + (O.N of CI) x 3 = 0 P + —2 + —1 x 3 = 0 —P — 2 — 3 = 0 P = — 5 (ii) I. NaNO is neutral because it is a salt of a strong acid and a strong base, its ions do not undergo hydrolysis. II. NHCI is acidic because it is a salt of a strong acid and a weak base. The NH undergoes hydrolysis. III. NaCO is basic because it is a salt of weak acid and ntrong base. The CO undergoes hydrolysis.
(c)(i) Hydrogen chloride gas (ii) downward delivery or upward displacement of air. (iii) The gas is denser than air (iv) drying the gas. (v) Physical properties — denser than air — very soluble in water — colourless gas — fumes in moist air Chemical Properties — gives cloud or white fumes in contact with ammonia vapour (vi) Pass the gas into AgNO a white precipitate of AgCl is formed wihich is soluble in aqueous ammonia but insoluble in HNO
(d) Mass of water = 4.30 — 2.12 = 2.18g Mass of NaSO = 23 x 2 + 32 + 16 x 4 = 142 Molar mass of HO = 2 + 16 = 18 2.12g of anhydrous salt contain 2.18g of water 142g of anhydrous salt contain = 146.018 X(HO) = 146 18x = 146 x = = 8