Consider the reaction represented by the equation. 2NaHCO3(s) \(\rightarrow\) 2Na2CO 3(S) + CO 2(g) + H2O(g) what volume of carbon (IV)oxide at s.t.p is evolved when 0. 5 moles of NaHCO3 is heated? [Molar volume = 22.4 dm3 at s.t. p]
A. 1.12dm3 B. 2.24dm3 C. 5.6dm3 D. 56.0dm3
Correct Answer: C
Explanation
2NaHCO3(s) \(\rightarrow\) 2Na2CO 3(S) + CO 2(g) + H2O(g) 2 moles of 2NaHCO3(s) produces 22.4dm3 of CO2 0.5 moles of 2NaHCO3 will produce \(\frac{0.5 \times 22.4}{2}\) = \(\frac{11.2}{2}\) = 5.6 dm3
