(a)(i)


(ii) At the anode Cu\(_{(s)}\) - 2e\(^-\) -> Cu\(^{2+}\)\(_{(ag)}\); At the cathode Cu\(^{2+}\) + 2e \(\to\) Cu\(_{(s)}\)
(iii) Daniell cell is an electrochemical cell because chemical energy (from the reaction between the electrodes and the solution) is converted into electrical energy.
(iv) The function of MnO\(_2\) in the Leclanche cell Pure copper plate is to serve as depolarizer that is preventing the impure copper (cathode) hydrogen gas from adhering to the anode.

(b)(i) In MnO\(^-_4\) - + 8H\(^+\) + xe\(^-\) \(\to\) Mn\(^{2+}\) + yH\(_2\)O ; x = 5, y = 4
(ii) The oxidation of Mn in MnO\(^-_4\) is +7.

(c)(i) - Position of the ions in the electro-chemical series
-Concentration of the ions in the electrolyte
-Nature of the electrode.
(ii) Faraday's second law oxosulphate of electrolysis states that when the same quantity of electricity is passed through different electrolytes the relative number of moles of the elements discharged are inversely proportional to the charge on the ions of each of the elements respectively.
(iii) AgNO\(_3\) and CuSO\(_4\) ; Ag\(^+\) + e\(^-\) -> Ag\(_{(s)}\) ; Cu\(^{2+}\) + 2e\(^-\) -> Cu\(_{(s)}\)
96500C will liberate 108; It liberated 0.780
It = \(\frac{0.780}{108}\) x 96500C = 696.9C

(d)(i) 2 x 96500 C will liberate 63.50 ; 696.9C will liberate
= \(\frac{696.9}{2 \times 96500}\) x 63.50 = 0.2293g.
(ii) The quantity of electricity = 696.2 C.
but Q = It ; 0.200 x t = 696.9
t = \(\frac{696.9}{0.200}\) = 3484.5s; = 58.075 mins.