If the cost of electricity required to discharge 10g of an ion X\(^{3+}\) is N20.00, how much would it cost to discharge 6g of ion Y\(^{2+}\)? [1 faraday = 96,500C, atomic masses are X = 27, Y = 24]
A. N10.00 B. N6.00 C. N20.00 D. N9.00
Correct Answer: D
Explanation
X\(^{3+}\) + 3e\(^-\) \(\to\) X 3F = 27g xF = 10g \(\frac{x}{3} = \frac{10}{27} \implies x = \frac{10}{9} F\) \(\frac{10}{9}\)F \(\equiv\) N20.00 1F is equivalent to x \(\frac{1}{\frac{10}{9}} = \frac{x}{20}\) \(\frac{9}{10} = \frac{x}{20} \implies x = N18.00\) 1F is equivalent to N18.00. Y\(^{2+}\) + 2e\(^-\) \(\to\) Y 2F = 24g xF = 6g x = \(\frac{6 \times 2}{24} = \frac{1}{2} F\) 1F = N18.00 \(\frac{1}{2}\)F = \(\frac{1}{2} \times N18.00\) = N9.00
