Given:
Current (I) = 2A; Time (t) = 2 hours = 7200 secs
Q = It
= 2 x 7200 = 14400C
1 F = 96500C
x = 14400C
x = \(\frac{14400}{96500}\)
= 0.15F
Mg\(^{2+}\) + 2e\(^-\) \(\to\) Mg
2F \(\to\) 24g
0.15F \(\to\) x
2x = 24 x 0.15
x = \(\frac{24 \times 0.15}{2}\)
= 1.8g