In the reaction between sodium hydroxide and tetraoxosulphate (VI) solutions, what volume of 0.5 molar sodium hydroxide would exactly neutralize 10cm of 1.25 molar tetraoxosulphate (vi) acid?
A. 25cm B. 10cm C. 20cm D. 50cm
Correct Answer: D
Explanation
Equation of reaction : 2NaOH + HSO → NaSO + 2HO Concentration of a base, CB = 0.5M Volume of acid, V = 10cm Concentration of an acid, C = 1.25M Volume of base, V = ? Recall: ... (1) N.B: From the equation, From (1) 25 = 0.5V VB = 50.0 cm