If 100cm3 of oxygen pass through a porous plug is 50 seconds, the time taken for the same volume of hydrogen to pass through the same porous plug is? [O = 16, H = 1]
A. 10.0s B. 12.5s C. 17.7s D. 32.0s
Correct Answer: B
Explanation
Rate of diffusion \(\frac{\alpha_1}{Density}\) or \(\frac{1}{\sqrt{Mm}}\) Rate = \(\frac{1}{time}\) \(\frac{1}{time}\) \(\frac{\alpha_1}{Density}\) or \(\frac{1}{\sqrt{Molarmass}}\) Time \(\alpha \sqrt{Density}\) or \(\sqrt{Molarmass}\) At constant volume of 100cm3 \(\frac{t_{o2}}{\sqrt{Mn_{o2}}}\) = \(\frac{t_{n2}}{\sqrt{1 \times 2}}\) \(\frac{50}{4 \sqrt{2}}\) = \(\frac{t_{n2}}{\sqrt{2}}\) tn2= 12.5s