Calculate the amount in moles of silver deposited when 9650C of electricty is passed through a solution of silver salt [= 96500 Cmol-1]
A. 0.05 B. 10.80 C. 10.00 D. 0.10
Correct Answer: D
Explanation
m = \(\frac{Mm \times Q}{96500n }\) where Q = IT M = Mm × \(\frac{Q}{96500n}\) where m = mass Mm = Molar mass Q = Quantity of electricity n = number of change= +1 \(\frac{M}{Mm}\) = mole = \(\frac{mass}{Molarmass}\) \(\frac{M}{Mm}\) = \(\frac{Q}{96500n}\) = \(\frac{9650}{96500n}\) × 1 = \(\frac{1}{10}\) = 0.1mol
