Chlorine consisting of two isotope of mass number 35 and 37 in the ratio 3:1 has an atomic mass of 35.5. Calculate the relative abundance of the isotope of mass number 37
A. 20 B. 25 C. 60 D. 75
Correct Answer: B
Explanation
Let the relative abundance of the energy with mass 37 be Total relative abundance of the isotope of mass 359100-k) Total mass of isotope of mass 37-37x, while that of 35-359(100x) -37x + 3500 − 35 − 35.5 -37x + 3500 − 35n − 35.5 Mean mass of chlorine atom − (2n + 3500)/ ÷ 100 = 35.5 2x + 3500 − 3550yx = 50/2
