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Cr 2O\(\frac{2 -}{7}\) (aq) + H 2O(1)⇌ 2CrO \(\frac{2 -}{4}\) (aq) ...

Cr 2O\(\frac{2 -}{7}\) (aq) + H 2O(1)⇌ 2CrO \(\frac{2 -}{4}\) (aq) + 2H + (aq)
What happens to the reaction above when the hydrogen ion concentration is increased?

A. more of the products will be formed
B. the reaction will not proceed
C. the equilibrium position will shift to the right
D. the equilibrium position will shift to the left.




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