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2H2 + O22 → H2+O ΔH = -571kJ In the equation above, ...

2H2 + O22 → H2+O ΔH = -571kJ
In the equation above, how much heat will be liberated if 12.0g of hydrogen is burnt in excess oxygen?

A. -1142 kJ
B. -571 kJ
C. +1142 kJ
D. -1713 kJ




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