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2SO2(g) + O2(g) ↔ 2SO3(g) ΔH = -189 kJ mol-1 The ...

2SO2(g) + O2(g) ↔ 2SO3(g)
ΔH = -189 kJ mol-1
The equilibrium constant for the reaction above is increased by

A. Increasing the temperature of the system
B. Increase the pressure of the system
C. The addition of a catalyst to the system
D. Increasing the surface area of the vessel




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