In a reaction: \(SnO_{2} + 2C → Sn + 2CO\) the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is? (Sn - 119, O - 16, C - 12).
A. 0.40 kg B. 0.20 kg C. 0.06 kg D. 0.04 kg
Correct Answer: C
Explanation
In the reaction: \(SnO_{2} + 2CO\) From the equation above 2(12 g) carbon = 151 g \(SnO_{2}\) 24 g carbon =151 g \(SnO_{2}\) = 0.302 kg \(SnO_{2}\) = 24/151g χ 0.0302 kg carbon = 0.048 kg carbon Mass of coke is required not mass of carbon,so it is (0.048\(\times\)100)\(\div\)80 = 0.06
