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N\(_2\)O\(_4\) ⇔ 2NO\(_2\) (Δ = -ve) From the reaction above, which ...

N\(_2\)O\(_4\) ⇔ 2NO\(_2\) (Δ = -ve)
From the reaction above, which of these conditions would produce the highest equilibrium yield for N\(_2\)O\(_4\)?

A. Low temperature and high pressure
B. Low temperature and low pressure
C. high temperature and low pressure
D. high temperature and high pressure




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