What volume of (dm\(^3\)) of water will be added to 10dm\(^3\) of 2.0 mol/dm\(^3\) HCL acid solution to give a final solution of 0.5 mol/dm\(^3\)?
A. 30 B. 40 C. 20 D. 50
Correct Answer: B
Explanation
To make a fixed amount of a dilute solution from a stock solution, use the formula: C1V1 = C2V2 where: V1 = Volume of stock solution needed to make the new solution. C1 = Concentration of stock solution. V2 = Final volume of new solution. C2 = Final concentration of stock solution 2 * 10 = 0.5 * V2 20 = 0.5V2 \(\frac{20}{0.5}\) = V2 = 40dm\(^3\) There is an explanation video available below.
