The correct answer is E. none.

Here’s the reasoning:

- The blindness of the man is likely caused by a recessive genetic condition, meaning the man would have two copies of the recessive gene (bb) for blindness.
- The one-eyed woman may have inherited the condition (likely due to a recessive gene for eye problems), but it depends on whether her condition is genetic and whether it’s dominant or recessive. If the one-eyed condition is also due to a recessive gene (and the woman is heterozygous, Xx, where X represents the normal gene and x represents the gene for the eye condition), then she has a 50% chance of passing on the recessive gene for the eye condition.

Since blindness in this scenario is likely caused by a recessive gene (bb), the children would inherit one copy of the b gene from the father and one from the mother if she carries the recessive gene. Since the woman would likely not be blind herself and only carries one copy of the recessive gene, none of the children would inherit two copies of the recessive gene for blindness.

Thus, none of the children would be blind like the father.